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Thread: Algebra.... Calling all Maths Boffins!

  
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    Algebra.... Calling all Maths Boffins! (also a quadratic at bottom of P3)

    I'm stuck on this little question. Does anyone wanna shed any light?

    The early stages of a construction project have been subjected to delays through bad weather. In an attempt to get the works back on schedule an additional sub-contracting gang has been employed for a period of three weeks. The total cost for the gang over this three week period was £10,320.00 based on a 40 hour week. The gang consisted of a Forman, a carpenter, a bricklayer and a labourer.

    Some time after the gang had left side your head office requests details of the hourly rate for each of the gang members. Site records did not provide the information but what was known was that the hourly rate for the carpenter was 70% of the foreman rate, the bricklayer earned £8.00 an hour less than the foreman and the labourer was paid at 40% of the bricklayer's rate.

    That's the story, the questions are:

    a. Devise a suitable equation which models the above scenario.
    b. Using this equation determine the hourly rate for each member of the gang.

    An help much appreciated! (I'll put up what I've got so far in a sec)
    Nova Merit: 2000-2003 // Irmschered Astra SRi: 2003-2005 // Leon Cupra R: 2005 - 2006 // Linea Rossa Convertible Turbo: 2006-2008 // BMW 840Ci: 2008 - 2012

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    Now I've been playing about and come up with this:

    If we call the Foreman's wages 'F':

    Foreman = F
    Carpenter = 0.7F
    Bricklayer = F-8
    Labourer = 0.4(F-

    and the total of all of them would equal £10320. Once you've worked out what each gets, you divide it by 3 to get the weekly amount and then by 40 to get the hourly rate.

    I just can't put it all into a nice tidy equation which gives me the answers I want.

    HELP!
    Nova Merit: 2000-2003 // Irmschered Astra SRi: 2003-2005 // Leon Cupra R: 2005 - 2006 // Linea Rossa Convertible Turbo: 2006-2008 // BMW 840Ci: 2008 - 2012

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    *wooooooooosh!!!!!!!!!!!*
    Thats just gone straight over my head and I thought I used to be good at maths
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    Know what you mean mate, I'm sure I should be able to do this standing on my head but everything I try comes out wrong. If it happened in real life I think I'd tell head office "computer says no"
    Nova Merit: 2000-2003 // Irmschered Astra SRi: 2003-2005 // Leon Cupra R: 2005 - 2006 // Linea Rossa Convertible Turbo: 2006-2008 // BMW 840Ci: 2008 - 2012

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    Taking the foreman's (F)hourly rate as X

    the carpenter, c = 0.7X
    the bricklayer, b = X-8
    the labourer, l = 0.4(X-

    total hourly rate = 10320/120 = £86 per hour.

    substituting

    86 = X + 0.7X + (X- + 0.4(X-

    You're a bright lad Steve, you can simply it down from here

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    Geoff you are the man!

    That's very similar to what I came up with but doesn't look anywhere near as complicated.

    Presumably I'd work out X first and then, using that work out the others based on:

    the carpenter, c = 0.7X
    the bricklayer, b = X-8
    the labourer, l = 0.4(X-
    Nova Merit: 2000-2003 // Irmschered Astra SRi: 2003-2005 // Leon Cupra R: 2005 - 2006 // Linea Rossa Convertible Turbo: 2006-2008 // BMW 840Ci: 2008 - 2012

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    Yep work everything out in 'X' and when you've gor the foremans hourly rate, plug it back into the others and get theirs

    Nay probs mate

    Bring on the calculus

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    Quote Originally Posted by Ffoeg
    Bring on the calculus
    Oh it's coming soon I think...
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    shit you quoted me - no going back now

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    Quote Originally Posted by Ffoeg
    shit you quoted me - no going back now
    LOL Surely you have moderating abilites to alter my post....
    Nova Merit: 2000-2003 // Irmschered Astra SRi: 2003-2005 // Leon Cupra R: 2005 - 2006 // Linea Rossa Convertible Turbo: 2006-2008 // BMW 840Ci: 2008 - 2012

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